CS2D
Scripts Round off decimal value
Round off decimal value
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) but I have a 'thing' that need to be solved.math.floor(x + 0.5).
math.flooror
math.ceil
math.floor(6.12314) > 6 math.floor(7.90999) > 7 math.floor(3) > 3 math.ceil(1.00001) > 2 math.ceil(5.93213) > 6 math.ceil(2) > 2
Starkkz said, use math.floor(x + 0.5)whether you want to round up if the fractional part of x is greater or equal than 0.5, or whether you want to round down if the fractional part of x is lower than 0.5.
math.floor(x - 0.5).
math.floor(x)
Offline-- As example only
local neardist = (contain-decimal-value)
if txt==("nearest") then
parse("msg2 "..id.." "..neardist)
end
Ace Howl: So what don't you get? It rounds the number. You can't add fractions in your head and see how it works..? I don't get you.math.floor(x + 0.5)does when x is:
1 0 421 420 777 Baloon: As Ace Howl said, the only thing you need to get distance is basic understanding of pythagorean theorem. They teach those in 5th-6th grade I guess, maybe earlier. math.floor(a)finds such integer n (n ∈ Z) that n ≤ a. Thus, for any positive number it will return that number without its fractional part - 0.3 becomes 0, 1.8 becomes 1, 17.5 becomes 17 etc. For any negative number, it will return the number before it, so -1.3 becomes -2, -4.75 becomes -5 etc.
math.floor(a+0.5)is that any number with a fractional part smaller than 0.5 retains the same integer part (0.3 + 0.5 is 0.8, the integer part is still 0), whereas for any number with a fractional part larger than or equal to 0.5 the integer part will increase by 1, and the fractional part will be removed (0.75 + 0.5 is 1.25, or 1 without the fractional part thanks to flooring).
local neardist = math.floor(math.sqrt((x-x2)^2+(y-y2)^2)+0.5) if (txt == "nearest") then msg2(id, neardist) end
local neardist = math.sqrt((x-x2)^2+(y-y2)^2) if (txt == "nearest") then msg2(id, math.floor(neardist+0.5)) end
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